Problema Solution

ON AN ALGEBRA TEST 39 MORE PUPILS PASSED THAN FAILED. oN A NEW TEST, 7 WHO HAD PASSED THE FIRST TEST FAILED, AND ONE THIRD OF THOSE WHO FAILED ON THE FIRST TEST PASSED THE SECOND TEST. AS A RESULT,31 MORE PASSED THE SECOND TEST THEN FAILED IT. WHAT WAS THE RECORD OF PASSING AND FAILING ON THE FIRST TEST?

Answer provided by our tutors

Write an expression for each statement:

:

Let x = number of students that originally failed

:

On an algebra test 39 more pupils passed than failed. 

(x+39) = number of students that passed originally

:

On a new test,

7 who had passed the first test failed,

(x+39) - 7 

x + 32 = Students who passed new test (from those that passed the 1st test)

: 

and one third of those who failed on the first test passed the second test. 

x = students who failed, passed the new test

:

As a result, 31 more passed the second test than failed it. What was the record of passing and failing on the first test?

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Total passing of the 2nd test: 

x + (x+32)

x + 32

:

Total failed the 2nd test: 

x + 7

;

2nd test

Passed - failed = 31

x + 32 - (x + 7) = 31

x + 32 - x - 7 = 31

x + 25 = 31

x = 31 - 25

x = 6

2x = 3 * 6

2x = 18 

x = 9 failed originally

then

9 + 39 = 48 passed originally

:

:

Check solution on the new test data:

12 + 32 = 44 passed (x + 32)

6 + 7 = 13 failed (x + 7)

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difference = 31