Problema Solution
Find two consecutive even integers if the sum of their recipricol is 9/40
Answer provided by our tutors
1/(x+2) + 1/x = 9/40
(x+x+2)/(x+2)x = 9/40
40(2x+2) = 9x(x+2)
80x+80= 9x^2 + 18x
9x^2 -62x - 80 = 0
solving this we will get x=8
so, integers are 8,10.