Problema Solution
an airplane climbs at an angle of 18 degrees with the ground. find the ground distance the plane travels as it moves 2500 m through the air. give your answer to the nearest 100 m.
Answer provided by our tutors
A
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| --------------------18
B-------------------------C
angle ACB = 18 degrees
AC = 2500 m = hypotenuse
AB = ? = perpendicular
sin 18 = perpendicular / hypotenuse
0.309 = AB/2500
Multiply both sides by 2500
0.309 x 2500 = AB
772.542 = AB
AB = 772.5
TO the nearest 100 m
Distance of plane from the ground = 800 m