Problema Solution
if an object is thrown upward with an initial velocity of 48ft/sec, its height after t sec is given by h=48t-16t^2. find the number of seconds before the object hits the ground.
Answer provided by our tutors
When it hits ground, h=0
48t-16t^2 = 0
t=0, t=3
So the number of seconds before the object hits the ground is t=3 sec