Problema Solution
The speed of train A is 10 mph slower than the speed of train B. Train A travels 230 miles in the same time it takes train B to travel 280 miles. Find the speed of each train
Answer provided by our tutors
D=RT
230=(R-10)T FOR THE SLOW TRAIN.
T=230/(R-10)
280=RT
T=280/R
230/(R-10)=280/R
280(R-10)=230R
280R-2,800=230R
280R-230R=2,800
50R=2,800
R=2,800/50
R=56 MPH FOR THE FASTER TRAIN.
56-10=46 MPH FOR THE SLOWER TRAIN.
PROOF:
230/46=280/56
5=5