Problema Solution
A rectangular brochure is designed so that it has an area of 32 square inches and a perimeter of 24 inches. Find the width and height of the brochure. Assume the height is greater than the width. (Round your answers to one decimal place.)
Answer provided by our tutors
Let l be length and b be breadth.
Area=32 sq inches
l*b=32 ----1
Perimeter=24 inches
2(l+b)=24
l+b=12
l=12-b ---2
Substituting value of l from 2 in 1, we get,
(12-b)b=32
12b -b2=32
b2-12b+32=0
b2-8b-4b+32=0
b(b-8)-4(b-8)=0
(b-4)(b-8)=0
b=4 or b=8
If b=4, l=8
If b=8, l=4
Since, l>b in case of a rectangle,
therefore, length=8 inches
breadth=4 inches