Problema Solution
The number of woman attending a conference was three less than twice the number of man. If 51 people attended the workshop, how many were women?
Answer provided by our tutors
"The perimeter of a rectangle is 28 feet."
2L + 2W = 28
"The length is 4 feet less than two times the width"
L = 2W - 4
By substitution,
2(2W - 4) + 2W = 28
4W - 8 + 2W = 28
6W = 36
W = 6
L = 2(6) - 4
= 8
:::::
"The number of women was three less than twice the number of men."
w = 2m - 3
"51 people attended the workshop"
w + m = 51
by substitution,
(2m - 3) + m = 51
3m = 54
m = 18
w = 51 - 18 = 33