Problema Solution
How many gallons of a 50% salt solution must be mixed with 60 gallons of a 21% solution to obtain a solution that is 40% salt?
Answer provided by our tutors
let ut requires x galons of 50% salt solution
then
(50x + 21*60)/(60+x) = 40
==> 50x + 1260 = 2400 + 40x
==> 10x = 1140
==> x = 114
hence, it requires 114 gallons of 50% salt solution