How many mg of a metal containing 45%...

Problema Solution

How many mg of a metal containing 45% nickel must be combined with 6 mg of pure nickel to form an alloy containing 78% nickel?

Let = mg of metal containing 45% nickel to be added

= nickel content of added metal

In words:

(mg of nickel in final alloy)/(mg of final alloy) = 78%

4 mg of 45% nickel metal must be added

check:

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