Problema Solution
The perimeter of a rectangle is 44 ft. The lenght is 4 ft. longer than the width. find the dimensions. Write a system of linear equations and solve the resulting system.
Let X be the length and y be the width
Answer provided by our tutors
The perimeter of a rectangle is 44 ft. The lenght is 4 ft. longer than the width. find the dimensions. Write a system of linear equations and solve the resulting system.
Let X be the length and y be the width
x = y + 4
2x + 2y = 44
2(y+4) + 2y = 44
2y + 8 + 2y =44
4y = 36
y = 9 ft --width
x = y + 4 = 9+ 4 = 13 ft -- length