Problema Solution

The perimeter of a rectangle is 44 ft. The lenght is 4 ft. longer than the width. find the dimensions. Write a system of linear equations and solve the resulting system.

Let X be the length and y be the width

Answer provided by our tutors

The perimeter of a rectangle is 44 ft. The lenght is 4 ft. longer than the width. find the dimensions. Write a system of linear equations and solve the resulting system.

Let X be the length and y be the width

x = y + 4

2x + 2y = 44

2(y+4) + 2y = 44

2y + 8 + 2y =44

4y = 36

y = 9 ft --width

x = y + 4 = 9+ 4 = 13 ft -- length