Problema Solution
The sum of a number and twice the second number is 56. The second number is 7 less than triple the first. Find the numbers.
Answer provided by our tutors
let one number is x and other number is y
from question
x+2y=56
y= 3x-7=> 3x-y=7
solving
7y= 70
=> y=10
x= 56-20=36