Problema Solution
If AB = x + 3, DB = 2x – 1, and BC = 3x – 5, what is the length of AC?
Answer provided by our tutors
AC = AB + BC = (x+3)+(3x-5) = 4x-2
So the length of AC is (4x-2)
If AB = x + 3, DB = 2x – 1, and BC = 3x – 5, what is the length of AC?
AC = AB + BC = (x+3)+(3x-5) = 4x-2
So the length of AC is (4x-2)