1) the slope is 2 and the graph passes through ordered pair (1,-5)..

The equation of the line is

(y+5) = 2(x-1)

y+5 = 2x-2

y = 2x-7

2) the slope is 0 and the graph passes through ordered pair (0,-7)..

The equation of the line is

(y+7) = 0(x-0)

y+7=0

y=-7

3) the slope is undefined and the graph passes through ordered pair (12,0)..

The equation of the line is

x-12=0

x=12

4) the slope is -1/3 and the graph passes through ordered pair (-6,-7)..

The equation of the line is

(y+7) = -1/3(x+6)

y+7=-x/3-2

y=-x/3 -9

5) the equation is parallel to the following equation y=-2/3x+5, and goes through the following ordered pairs (6,-7)

Let the equation of the required line be

y = (-2/3)x+k ...(1)

The point (6,-7) lies on it

So, -7 = (-2/3)*6+k

-7 +4=k

k=-3

So, (1) => the equation of the required line be

y = (-2/3)x - 3

6)the equation is perpendicular to the following equation y=-2/3x+5, and goes through the following ordered pairs (6,-7)

The slope of the given line = -2/3

The slope of the perpendicular line is 3/2

The equation of the required line is

y+7 = (3/2)(x-6)

y = (3/2)x-9-7

y = (3/2)x-16