I will walk you through with one.

(6, -5) and is parallel to the line whose equation is 2x - 3y = 11?

2x - 3y = 11

add 3y to both sides

2x=11+3y

-11

2x-11=3y

3y=2x-11

/3

y= (2/3)*x-11/3

slope m = 2/3

The parallel line will have the same slope as that of the given line.

so slope of the required line will be 2/3

..

line passes through (6,-5)

plug the value of slope , and the point (6,-5) to find b the y intercept

of the required line

y=mx+b

-5=2/3 *6+b

-5=4+b

b=-9

...

so the equation has slope 2/3 and y intercept -9

y=(2/3)x-9