Problema Solution
A box contains nickels, dimes, and quarters worth $12.60. The number of dimes is 2 less than three times the number of nickels, and the number of quarters is 4 less than twice the number of dimes. How many of each coin are there?
Answer provided by our tutors
N = the number of nickels
D = the number of dimes
Q = the number of quarters.
N*.05 + D*.10+Q*.25 = 12.6
D = 3*N - 2 --> N = (D +2)/3
Q = 2*D - 4
(D+2)*.05 + D*.30+(2*D-4)*.75 = 12.6*3, so D = 22
then N = 8 and Q = 40