Problema Solution
The perimeter of a rectangle is 36ft. The length is 2 ft longer than the width. Find the dimensions. Write a system of linear equations and salve the resulting system. let x be the length and y be the with.
write the first equation: 2x+2y=
write the second equation: x=y+
What is the length?
What is the width?
Answer provided by our tutors
Let x = width y= length or x+2=length
2x + 2(x+2) =36
y=x+2
y-2=x+2-2
y-2= x or x = y + (-2)
2x + 2x + 4 = 36
4x +4 =36
4x+4-4 = 36-4
4x=32
4x/4 = 32/4
x= 8
length--x+2
8+2 =10 feet
width 8 feet