Problema Solution
In ten years time a father age will be twice as his son age, ten years ago he was six times as old as his son. How old are both of them
Answer provided by our tutors
f+10 = 2(x+10) ==> 3f + 30 = 6(x+10)
f-10 = 6(x-10) ==>
3f + 30 - f+10 = 120
2f + 40 = 120 ==> 2f = 80 f = 40 and s = 15