Problema Solution
if a basketball player had a vertical leap of 35 inches, what is his hang time? use the hang-time function v-48t^2
Answer provided by our tutors
Given: about 35 inches
Means: V = 35
Plug this into the given function.
V = 48T^2
35 = 48T^2
Divide both sides by 48.
35 / 48 = 48T^2 / 48
35 / 48 = T^2
Take the square root both sides.
± √(35 / 48) = ±√(T^2)
T = ± 0.853912564
Round to the nearest tenth.
T ≈ ± 0.9
Since time cannot be negative:
T ≈ 0.9
Answer: 0.9 seconds