3. One leg of a right triangle is 24 in long and the hypotenuse is 6 in shorter than twice the length of the other leg. Find its perimeter.

            (2x - 6)2 = x2 + 576

          3x2 - 24x - 540 = 0

            x2 - 8x - 180 = 0

            x2 - 18x + 10x - 180 = 0

             x(x -18) + 10(x - 18) = 0

               (x - 18)(x + 10) = 0

                        x = 18

            Perimeter = 24 + 18 + (2*18 - 6) = 24 + 18 + 30 = 72 inches

4. The side of one square is 4 in longer than that of a second square. The area of the larger is 32 sq. in less than twice the area of the smaller. Find the perimeter of each square.

                                     (x + 4)2 - x2 = 32

                                         8x + 16 = 32

                                            x = 2 inch

Perimerter of smaller square = 8 inches

Perimerter of larger square = 24 inches