Problema Solution
A bicycle rider left at 6 a.m. city A to city B at the speed of 15 km an hour. At 8 a.m. a car left city A for city B at the speed of 75 km an hour.
The car arrived to B, stayed there 2 hours and started driving back to A at the same speed. After a 1/4 of the way back the car met the bicycle.
What is the distance between A to B?
Answer provided by our tutors
the distance between A to B is x
So
(x/75 +2)*15 + (1/4)x + (1/20)x = x
x=60
So the distance between A to B is 60 km