Problema Solution
A carpenter is building a rectangular room with a fixed perimeter of 320 ft. What dimensions would yield the maximum area? What is the maximum area?
Answer provided by our tutors
so 240=2*(l+b)so
l+b=120
so if l=x
b=120-x
area=x*(120-x)
A=x(120-x)
for maximum A dA/dx=0
dA/dx=d/dx(120x-x^2)
0=120-2x
x=60ft
length=60ft
breadth=120-60=60ft answer
area = 60* 60 = 3600 sq ft