Problema Solution
how many gallons of 80 % antifreeze solution must be mixed with 90 gallons of 20 % antifreeze to get a mixture that is 70 % antifreeze
Answer provided by our tutors
if z is the answer then you are going to end with (70 + z) gallons of solution to find out what z is you use this formula: .8z + (70 x .3) = .7(z + 70) this yields: .8z - .7z = 49 - 21 .1z = 28 or z = 280