Problema Solution
find two consecutive even integers whose product is 624
Answer provided by our tutors
(2n) (2n + 2) = 624
4n² + 4n - 624 = 0
n² + n - 156 = 0
(n + 13) (n - 12) = 0
n = - 13 , n = 12
Integers are 24 and 26
find two consecutive even integers whose product is 624
(2n) (2n + 2) = 624
4n² + 4n - 624 = 0
n² + n - 156 = 0
(n + 13) (n - 12) = 0
n = - 13 , n = 12
Integers are 24 and 26