find the length and width of a rectanglar lot with a perimeter of 108 meters if the length is 8 meters more than the width

let x = length

  y = width

2x + 2y = 108

x = y + 8

2(y+8) + 2y = 108

2y + 16 + 2y = 108

4y = 92 

y  = 23 meters

x = y + 8 = 23 + 8 = 31 meters