Problema Solution
Joe has a collection of nickels and dimes that is worth $6.10. If the number of dimes was tripled and the numbe of nickels was increased by 49, the value of the coins would be $18.95. How many nickels and dimes does he have?
Answer provided by our tutors
NUMBER OF NICKELS =N
DIMES = D
VALUE OF N, NICKELS = $0.05N
D DIMES = $0.1D
0.05N+0.1D=6.1
0.05(N+49)+0.1(3D)=18.95
0.05N+2.45+0.1(3D)=18.95
0.05N+0.3D=16.5
0.05N+0.1D=6.1
D=52 AND N=18