Problema Solution
If the perimeter of the triangle is 45cm and long side is exceed the short side by 8 and sum of long or short is twice of other side .Then find the sides of triangle
Answer provided by our tutors
let the short side be x
long side is x+8
other side is 2x+8/2
perimeter is 45
2x+8+ (2x+8)/2=45
4x+16+2x+8=90
6x=66
x=11
x+8=19
other side is 15