Problema Solution
A man has a 50 kilograms mixture that is one-third cement and two-third sand. How much of a mixture that is half cement and half sand must be added to the 50 kilogram mixture to produces a mixture that is two-fifths cement and three-fifths sand?
Answer provided by our tutors
ans is 100/3 kg
cement in first mix =50/3
let v kg of second is added
cement in second =v/2 kg
total =v/2+50/3
this must be equal to 2/5 of total
v/2+50/3= 2/5 *(50+v)
solve for v