Problema Solution
A red car leaves NYC going north at 11:00am. A blue car leaves Albany going south at 1:00pm going 10 mph slower than twice the speed of the red car. The distance between the two cities is 220 miles. If the two cars meet at 3:00pm, how fast was the red car going?
Answer provided by our tutors
Let the speed of the red car be x
Blue car tavles 10mph slower than twice speed of red car
So speed of blue car = 2x - 10
The cars meet at 3 pm.
So, time for which the red car travelled = 4 hours
time for the blue car = 2 hours
Distance for red car = speed x time = 4x
Distance for blue car = speed x time = 2(2x-10) = 4x - 20
Now it is said that distance between 2 cities = 220 miles
so
4x + 4x - 20 = 220
8x - 20 = 220
8x = 240
x= 30
So red car was going at 30mph.