Problema Solution
The volume of a pyramid is given by the formula
V = bh/3
where B is the area of its base and h is its height. The volume of the following pyramid is 88 cubic centimeters. Find the dimensions of its rectangular base if one edge of the base is 2 centimeters longer than the other and the height of the pyramid is 11 centimeters.
cm (smaller value)
cm (larger value)
Answer provided by our tutors
Volume (V) = 1/3 x Area of base (B) x Perpendicular height (H)
Consider that length of the base is (L + 2) and breadth is L
88 = 1/3 x L(L + 2) x 11
264 = 11L(L + 2)
11L(L + 2) = 264
L (L + 2) = 24
L2 + 2L = 24
L2 + 2L - 24 = 0
L2 + 6L - 4L - 24 = 0
L(L + 6) - 4(L + 6) = 0
(L + 6 ) (L - 4) = 0
then L + 6 = 0 or L - 4 = 0
then L = - 6 and L = 4
But length can not be negative. Which L > 0
4 cm is more suitable for L
Length = L + 2 = 6cm
Breadth = L = 4cm
Answered By
U S M C PERERA
An Educationist from the University of Sri Jayewardena Pura (Sri Lanka)
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