Problema Solution
Two cyclists, 64 miles apart, start riding toward each other at the same time. One cycles 3 times as fast as the other. If they meet 2 hours later, what is the speed (in mi/h) of the faster cyclist?
Answer provided by our tutors
x = faster cyclist speed
y = slower cyclist speed
x = 3y
y = x/3
x/2 + y/2 = 64
x/2 + (x/3)/2 = 64
(x/2 + x/6 = 64)(6)
3x + x = 384
4x = 384
x = 96 mi/hr