Problema Solution
How many four-character codes can be formed if the first character is a nonzero digit, the second character is an odd digit, the third character is any digit, and the last character is a letter of the alphabet, and repetition of digits is allowed. (A digit is 0,1,2,3,4,5,6,7,8 or 9.)
Answer provided by our tutors
9 x 5 x 10 x 26
= 11,700
9 non-zero digits 1,2,3,4,5,6,7,8,9
5 odd digits 1,3,5,7,9
10 digits 0,1,2,3,4,5,6,7,8,9
26 letters in the alphabet