Problema Solution
Find three consecutive integers such that 3 times the third integer is 15 more than the sum of the first two.
Answer provided by our tutors
x, x+1, x+2.
so,
3(x+2) = 15 + x + x + 1
3x + 6 = 2x + 16
x = 10.
So, numbers are 10, 11, 12.