Problema Solution
The volume V of a given mass of gas varies directly as the temperature T and inversely as the pressure P. A measuring device is calibrated to give V= 364in^3 when T= 260 degrees and P = 101lb/in^2. What is the volume on this device when the temperature is 300 degrees and the pressure is 251lbs/in^2?
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We have V=kT/P. From your info, 364=k x 260/101 and k=364x101/260=141.4. So for your problem V=141.4x300/251=169in^3