Problema Solution
If a 6-person volleyball team is selected at random from a 12 club 5mens and 7 women members.What is the probability the team consists of 2 men and 4 women?
Answer provided by our tutors
No. of Players-12
No. of men-5
No. of Women-7
No of Players Selected-6(4 women,2 men)
Solution- (12C6)*(7C4)*(5C2)
6 players can be chosn from a total of 12 in 12C6 ways
among them 4 women can be selected out of 7 in 7C4
and 2 men in 5C2 ways.
using bayes theorem-
probability of this selection =
(probalibilty of selecting 4 women and 2 men)/((probability of selecting 6 women 0 men)+(probability of selecting 5 women 1 man)+(probablity of selecting 4 women and 2 men)...(probablity of selecting 1 woman and 5 men))
=(323400)/((924)+(6468)+(323400)+(323400)+(97020)+(32430))
=0.41268