Problema Solution
In a certain manufacturing process, the probability of a type I defect is 0.08, the probability of a type II defect is 0.13, and the probability of having both types of defects is 0.06.
Find the probability that neither defect occurs.
Answer provided by our tutors
P(I) = 0.08
P(II) = 0.13
P(I and II) = 0.06
Now,
P(I or II) = P(I) + P(II) - P(I and II)
So, P (I or II) = .08 + .13 - .06 = .15
To find probability of neither of the defects occuring , subtract the probability of either of them occuring from 1
Thus required probabilty = 1 - P(I or II) = 1-.15 = .85
The probability that neither defect occurs = .85