Problema Solution
Standard form of the equation of an ellipse with Vertices (17,5) and
(-9,5) and foci (9,5) and (-1,5)
Answer provided by our tutors
This is an ellipse with horizontal major axis.
Its standard form of equation: (x-h)^2+(y-k)^2=1, a>b, (h,k)=(x,y) coordinates of center.
For given ellipse:
center(0,0)
a=5
a^2=25
c=3
c^2=9
c^2=a^2-b^2
b^2=a^2-c^2
b^2=25-9=16
Equation for given ellipse:
x^2/25+y^2/z16=1
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19. Find the standard form of the equation of the ellipse with minor axis of length 6, center at (5,-1) and a focus at (-1,-1).
This is an ellipse also with horizontal major axis.
Its standard form of equation: (x-h)^2+(y-k)^2=1, a>b, (h,k)=(x,y) coordinates of center.
For given ellipse:
center: (5,-1)
2b=6
b=3
b^2=9
c=(5-1/2=4/2=2
c^2=4
c^2=a^2-b^2
a^2=c^2+b^2=4+9=13
a^2=13
a≈√13≈3.6
Equation for given ellipse:
(x-5)^2/13+(y+1)^2/9=1