Problema Solution
In a competitive eating competition, two of the competitors can eat a total of 540 chicken wings in 6 hours.
Eating on his own, competitor A would take 18 hours longer than Competitor B to eat the 540 chicken wings.
How long would it take competitor B to eat the 540 chicken wings on his own?
Answer provided by our tutors
In a competitive eating competition, two of the competitors can eat a total of 540 chicken wings in 6 hours.
Eating on his own, competitor A would take 18 hours longer than Competitor B to eat the 540 chicken wings.
In one hour B can eat 540/x of wings.
In one hour A can eat 540/(1/18+x) of wings.
In one hour both can eat 540/6
540/x+540/(18+x)=540/6.
1/x+1/(18+x)=1/6.
(18+x+x)/(x(18+x)=1/6.
(18+2x)/(x^2+18x)=1/6.
x^2+18x=6(18+2x)=
x^2+18x-12x-108=0.
x^2+6x-108=0.
By solving quadartic we have t=7.82Hours.