Problema Solution
5 years ago, a mother was twice as old as her son. In 6 years time, the sum of their ages will be 82. Find their present ages.
Answer provided by our tutors
Let the present age of mother be x years and son is y years
x-5 = 2(y-5)
x+6+y+6 = 82
x= 70-y
65 - y = 2y -10
3y = 75 y =25 years
Mom is 70 -25 = 55 years