Problema Solution
The perimeter of a rectangle is equal to twice the sum of its length and width. Find the perimeter with a length 40 ft. and a width 9 ft.
Answer provided by our tutors
P = 2L + 2W
= 2*40 + 2*9
= 80 + 18
= 98
The perimeter of a rectangle is equal to twice the sum of its length and width. Find the perimeter with a length 40 ft. and a width 9 ft.
P = 2L + 2W
= 2*40 + 2*9
= 80 + 18
= 98