Problema Solution
how many gallons of 90% antifreeze solution must be mixed with 80 gallons of 10% antifreeze to get a mixture of that 80%antifreeze?
Answer provided by our tutors
let x gallons of 90% mixed with 80 gallons of 10% antifreeze
so the total antifreeze = x*90/100 + 80*10/100 = 0.9x+8
total volume = x+80
(0.9x+8)/ x+80 = 0.8
0.9x+8 = 0.8x+64
0.1x = 56
x = 560 gallons
so we needto mix 560 gallons of 90% antifreeze