Problema Solution
suppose you have a coin collection of dimes and quarters containing 46 coins. If you have $6.70, how many of each type of coin do you have?
Answer provided by our tutors
Let say we have x dimes and y quaters.
All together we have 46 coins.
x+y = 46 ----(1)
We have $6.7 from the coins.
One dime cost $0.1 and one quater cost $0.25.
0.1x+0.25y = 6.7
We will multiply the above by 100 to remove the decimals.
10x+25y = 670 -----(2)
Now we have to solve (1) and (2) linear equations.
(2)-10*(1)
25y-10y = 670-460
15y = 210
y = 14
From (1) x = 46-14 = 32
So we have 32 dimes and 14 quaters.