Problema Solution
A model rocket is launched with an initial upward velocity of
39/ms
. The rocket's height
h
(in meters) after
t
seconds is given by the following.
=h−39t5t2
Find all values of
t
for which the rocket's height is
22
meters.
Round your answer(s) to the nearest hundredth.
(If there is more than one answer, use the "or" button.)
Answer provided by our tutors
Assuming the formula for height is h = 39t - 5t^2 we need to solve:
39t - 5t^2 = 22
........
click here to see the equation solved for t
........
t1 = 7.19 s
t2 = 0.61 s
The value for t for which the rocket's height is 22 m are 7.19 s and 0.61 s.