Problema Solution

A model rocket is launched with an initial upward velocity of

39/ms

. The rocket's height

h

(in meters) after

t

seconds is given by the following.

=h−39t5t2

Find all values of

t

for which the rocket's height is

22

meters.

Round your answer(s) to the nearest hundredth.

(If there is more than one answer, use the "or" button.)

Answer provided by our tutors

Assuming the formula for height is h = 39t - 5t^2 we need to solve:

39t - 5t^2 = 22

........

click here to see the equation solved for t

........

t1 = 7.19 s

t2 = 0.61 s

The value for t for which the rocket's height is 22 m are 7.19 s and 0.61 s.