Problema Solution
A ball is thrown vertically upward. After
t
seconds, its height
h
(in feet) is given by the function
=ht−48t16t2
. After how long will it reach its maximum height?
Answer provided by our tutors
h(t)=48t-16t^2
The graph of h(t) is parabola opening downwards and the maximum height will be the vertex:
x-coordinate of the maximum is:
k = -b/2a, where a = -16, b = 48
k = -48/(2*16)
k = 1.5 s
After 1.5 seconds the ball will reach its maximum height.