Problema Solution
sum of three numbers is 16. The sum of twice the first​ number, 5 times the second​ number, and 6 times the third number is 61. The difference between 8 times the first number and the second number is 61.
Find the three numbers.
Answer provided by our tutors
Let 'x' represent the first number, 'y' the second number and 'z' the third number.
The problem statement is ambiguous because 'the different between 8 times the first number and the second number' does not definitely state whether '5x-6y' or '6y-5x' is intended.
We can assume these equations:
x+y+z=15
2x+5y+6z=61
8x-y=61
click here to solve for x , y and z
x=8
y=3
z=5
So the three numbers are 8, 3 and 5.