Problema Solution
suppose 3,000 is invested at 6% interest compounded continuously. how long will it take for the investment to grow to 12,000
Answer provided by our tutors
Let
P = $3,000 the principal (the investment)
t = the time in years
r = 0.06 or 6% the annual interest rate
A = $12,000 the future value (the investment will double in size)
The future value formula for continuous compounding is:
A=Pe^(rt)
Plug the values into the formula:
12000= 3000e^(0.06t)
e^(0.055t) = 12000/3000
e^(0.055t) = 4
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t = 23.1 years
It will take 23.1 years for the investment to grow to $12,000.