Problema Solution
Suppose two people begin walking in the same direction at different average speeds. Walker A starts at the 0.5-meter mark and walks at a speed of 1 m/s. Walker B starts at the 2-meter mark and walks at a speed of 0.5 m/s. When and where will Walker A pass Walker B?
Answer provided by our tutors
Let
v1 = 1 m/s the speed of walker A
v2 = 0.5 m/s the speed of walker B
t = the time of the walk
Since distance = speed*time we have:
0.5 + v1t = 2 + v2t
0.5 + 1*t = 2 + 0.5t
........
click here to see the equation solved for t
........
t = 3 s
0.5 + 1*3 = 3.5 m
Walker A will pass Walker B after 3 seconds.
Walker A will pass Walker B after 3.5 meters.