Problema Solution
Suppose you drive 28 miles to a thanksgiving dinner and it takes you 1.26 hours to get there. Suppose that your speed during the second 14 miles was 5 MPH faster than your speed during the first 14 miles. What was your speed during the first 14 miles?
Answer provided by our tutors
Let
v = the speed during the first 14 miles, v>0
v + 5 = the speed during the second 14 miles
Since speed = distance/time follows time = distance/speed.
So now we can write:
14/v + 14/(v + 5) = 1.26
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click here to see the equation solved for v
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v = 20 mph
The speed during the first 14 miles was 20 mph.