Problema Solution
The diagonal of a rectangle measures 3sqrt(6) inches. If the width is 6 inches less than the length, then find the dimensions of the rectangle.
Answer provided by our tutors
d = 3√6
x = length
x - 6 = width
Using the Pythagorean Theorem:
d^2 = x^2 + (x - 6)^2
x^2 + (x - 6)^2 = d^2
x^2 + (x - 6)^2 = (3√6)^2
........
click here to see the equation solved for x
........
x = 7.24 in
x - 6 = 7.24 - 6 = 1.24 in
The dimensions of the rectangle are: the length is 7.24 in while the width is 1.24 in.