Problema Solution
the diagonal of a rectangular room is 52 ft long. One wall measures 28 ft longer than the adjacent wall. Find the dimensions of the room.
Answer provided by our tutors
Let
d = 52 ft is the diagonal
w = the width of the room, w>=0
l = w + 28 ft the length of the room
Using the Pythagorean Theorem we can write
w^2 + l^2 = d^2
w^2 + (w + 28)^2 = 52^2
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click here to see the step by step solution for w
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w = 20 ft
We need to ignore the negative solution since w>=0.
l = w + 28
l = 20 + 28
l = 48 ft
The dimensions of the room are 20 ft by 48 ft.