Problema Solution
The diagonal of the rectangle is 8 meters longer than its shorter side. If the area of the rectangle is 60 square meters, find the dimensions.
Answer provided by our tutors
Let 'x' represent the shorter side then the diagonal is '8 + x'.
The longer side is equal to √((8 + x)^2 - x^2) = √(64 + 16x)
The area of the rectangle is 60 m^2 means that:
x*√(64 + 16x) = 60
x^2(64 + 16x) = 60^2
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click here to see the equation solved for x
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x = 5 m
x + 8 = 5 + 8 = 13 m
The dimensions of the rectangle are 5 meters and 13 meters.